So, in order.
There is no limit to perfection.
Better then d:(v=2)!(v=8)!(v=9) t3case289 q- There are one error in the Test2 method:
s:'$d(addr) addr(1)=1, (addr(2),addr(8),addr(9))=289, add(3)=3
- There are error in the Test3 method:
d:v=1 t3case1 Q ;will work in any way
d:v=2 t3case289 Q d:v=8 t3case289 Q d:v=9 t3case289 Q d:v=3 t3case3 Q d t3case Q - Speed will depend on many factors: RAM size, number of conditions (the more of them, the slower the lasts of them will be executed and more RAM is required).
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