Round to next whole number
How can I round to the next whole number?
.1 = 1
1.2 = 2
1.7 = 2
Comments
Here's one lazy option:
USER>w $System.SQL.CEILING(.1) 1 USER>w $System.SQL.CEILING(1.2) 2 USER>w $System.SQL.CEILING(1.7) 2
If you look at the implementation of that method in %SYSTEM.SQL, you'll see:
$s('$isvalidnum(val):"",+val[".":+$p(val,".")+(val>0),1:+val)So that's another option (although messier).
Perfect, Thanks!
Don't rely too much on this !
w $System.SQL.CEILING(1.000000000000000001)
2
w $System.SQL.CEILING(1.0000000000000000001)
1
Not a problem with the function itself.
w 1.0000000000000000001
1
Ceiling, floor, $NORMALIZE. Examples:
>Write $SYSTEM.SQL.CEILING(.1)
1
>Write $SYSTEM.SQL.CEILING(1.2)
2
>Write $SYSTEM.SQL.CEILING(1.7)
2
>Write $SYSTEM.SQL.FLOOR(.1)
0
>Write $SYSTEM.SQL.FLOOR(1.2)
1
>Write $SYSTEM.SQL.FLOOR(1.7)
1
>Write $NORMALIZE(.1, 0)
0
>Write $NORMALIZE(1.2, 0)
1
>Write $NORMALIZE(1.7, 0)
2If you have limited decimal places, there's always the old MUMPS way 
F I=0.1:0.1:10 W !,I,?5,$J(I+.49999999999,0,0)
You could also use plain ol' integer division plus 1.
USER>w .1\1+1
1
USER>W 1.2\1+1
2
USER>W 1.7\1+1
2
USER>
[EDIT] As pointed out by Carlos Lopes, this method fails for integer input:
USER>W 1\1+1
2
This approach would fail for integers.
USER>Write 1\1+1
2
It sure would. I hadn't considered integer input. Thanks for pointing that out!
but that way
USER>f a=0.8:.1:2.2 w a,?7,a\1+(a#1>0*1),?10,!
.8 1
.9 1
1 1
1.1 2
1.2 2
1.3 2
1.4 2
1.5 2
1.6 2
1.7 2
1.8 2
1.9 2
2 2
2.1 3
2.2 3
set a=1.2 // your number
write a\1+''(a#1) // this is a NOT NOT and not a quote!