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· Feb 15, 2018

Retrieving REST Data

#REST API #Caché

I'm sending data via ajax to my REST service, and while retrieving any information sent in the url parameter is easy when they're defined in the route, I can't get anything if I store information in the data parameter. For example:

$.ajax({
               url: "ServerURL",
               data: { "some": "json" } //How do I get this information?

...

I've looked at many common solutions such as here:

https://community.intersystems.com/post/lets-write-angular-1x-app-cach%C3%A9-rest-backend-part-9

However, %request seems empty for the most part. I can get the url of the request and the method type, but Data, Content, Content.Read(), etc. are always empty. I feel like something simple is missing here that I'm not seeing. Any help is appreciated!

Thanks,

David

Discussion (8)2
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David Crawford · Feb 15, 2018

Yes, this is the whole call, with the intention of receiving whatever I sent back to me:

$.ajax({
                headers: { "Authorization": "Basic " + btoa("username:password") },
                url:"serverurl/returnresponse",
                type: "POST",
                data: {
                    "payload": "some data"
                },
                success: function (response) {
                    console.log(response);
                }

});

 

Then the route:

<Route Url="/returnresponse" Method="POST" Call="ReturnResponse" Cors="false"/>
 

The method:

ClassMethod ReturnResponse() as %Status {
    try {
        set obj = %request.Data //...Contents...etc.
        write obj   
    }
    catch ex {
        write ex.Name
    }
    return $$$OK
}

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David Crawford · Feb 15, 2018

Fantastic! This is perfect, thank you so much!

From your example, at a minimum I had to add two parameters to my ajax:

contentType: "application/json",
dataType: "json",

And then to retrieve them, the REST service simply needs this to send back to the client whatever was in the message:

set jsonstring = $ZCONVERT(%request.Content.Read(),"I","UTF8")
set data = {}.%FromJSON(jsonstring)
write data.%ToJSON()

Thanks again!

David

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