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Member since Mar 2, 2016
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$LISTBUILD (IDs of referenced objects) should do the trick. The "parent" table here is only storing the corresponding IDs not the entire objects. You need to save each object individually and then link them.

While the object counterpart takes care of saving/inserting both objects in memory, the same is not true for SQL. You need to treat each object as individual rows on different tables.

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