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· Jun 14, 2018

Extending and compiling with XMLEnable issue

#Object Data Model #XML #Caché

Hello All,

I hope it's not a silly question. 

Here is my issue:
I have 3 simple classes:

Parent class, let's say:

Class ParentClass Extends %RegisteredObject
{
 Property a As %String;
}
 
and two children classes
Class A.Child Extends ParentClass
{
Property b As %String;
}

Class B.Child Extends ParentClass
{
Property c As %String;
}

So no issues - all compiles and seem to work.

But, when I add %XML.Adaptor to my parent class, so:

Class ParentClass Extends (%RegisteredObject, %XML.Adaptor)
{
 Property a As %String;
} 

I can no longer compile any of the three classes involved and I get this error:
---------------------------
Studio
---------------------------
ERROR #6281: XMLTYPE of class A.Child must be able to differentiate child classes of ParentClass.
  > ERROR #5090: An error has occurred while creating projection ParentClass:XMLEnabled.
---------------------------
OK   
---------------------------

Please advice if there is a way to workaround this error, or if it's simply cannot work with %XML.Adaptor.

Thank you,
Alex

Discussion (3)1
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Robert Cemper · Jun 14, 2018

Alex,
add Parameter  

Parameter XMLTYPE = "A_CHILD";

to one of your child classes
inherited comment is somewhat vague:

/// This parameter provides the default XMLTYPE for the class. If it is
/// empty then the class name will be used to construct a default XML type.
/// 
/// The default XMLTYPE is used when naming and referencing this type
/// in a schema and the schema context did not provide an XML type name.

documentation  is more precise:

For an XML-enabled class or a property that is based on an XML-enabled class, the XML type is determined as follows:
If the class has a value for the XMLTYPE parameter, that is used as the type name.
Otherwise, the short class name is taken as the XML type name.

so you would have 2 different classes with the same type:  CHILD
that's not allowed in an XML schema they have to be unique.

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