creating a macro with an unknown number of parameters
I use macros everyday, but its the first time I want to create a macro like this
I want to create a new macro whereby I can pass a variable amount of parameters
the macro (much simplified version) would be
#define myMacro(%params) $listBuild(any Number Of %params I pass in)
so I want to be able to call $$$myMacro(user,ID,vehicle) ie 3 parameters would generate
$lb(user,ID,vehicle)
but equally I might want to call that same macro $$$myMacro(companyID) ie 1 paramter and would generate
$lb(companyID)
so the question is,
how can I create the macro without knowing how many parameters I'm passing in up front.
(Hope this makes sense)
kevin
Use def1arg macro definition:
Compiles into
that doesn't seem to work Eduard.
here's my macro (according to you)
#define testEmptyParams(%args) i $listfind($listbuild("%args"),"")>0 $$$quitMissingParamshere's the call
$$$testEmptyParams(ExtID,UserID,originalVehicleID,newVehicleID,reasonID)when I compile that, I get
"Too many arguments to macro: 'testEmptyParams'"
I've tried removing the quotes inside the macro and it still says too many arguments.
so I want to do a nested $lb, and then quit with another macro $$$quitMissingParams.
because I'm testing for empty parameters, I never know how many params I want to pass in.
example
s a="1",b="2" i $listfind($listbuild(a,b),"")>0 w " - missing"s a="",b="2" i $listfind($listbuild(a,b),"")>0 w " - missing"s a="",b="2",c=3 i $listfind($listbuild(a,b,c),"")>0 w " - missing"s a="1",b="2",c=3 i $listfind($listbuild(a,b,c),"")>0 w " - missing"Am I missing something ?
Does my example compile for you?
Anyway, you should use #def1arg instead of #define as I suggested in the original answer.
I apologise,
I am so used to using #define, I totally missed the #def1arg
so, now I change it to this, It works fine.I hadn't come across this #def1arg before.
Its an interesting use and I can think of quite a few ways already where I can create more macros to make use of it.
thanks
kevin